If the truth value of the expression [(p vee | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The implication $A \rightarrow B$ is False if and only if $A$ is True and $B$ is False.Here,$A = [(p \vee q) \wedge (q \rightarrow r) \wedge (\sim

Vedclass · Accepted Answer

$T, F, F$

Vedclass · Answer

(B) The implication $A \rightarrow B$ is False if and only if $A$ is True and $B$ is False.Here,$A = [(p \vee q) \wedge (q \rightarrow r) \wedge (\sim r)]$ and $B = (p \wedge q)$.For $B = (p \wedge q)$ to be False,at least one of $p$ or $q$ must be False.For $A$ to be True,all components $(p \vee q)$,$(q \rightarrow r)$,and $(\sim r)$ must be True.From $(\sim r) = T$,we get $r = F$.Substituting $r = F$ into $(q \rightarrow r) = T$,we get $(q \rightarrow F) = T$,which implies $q = F$.Now,substitute $q = F$ into $(p \vee q) = T$,we get $(p \vee F) = T$,which implies $p = T$.Checking $B = (p \wedge q) = (T \wedge F) = F$,which satisfies the condition.Thus,the truth values are $p = T, q = F, r = F$.

If the truth value of the expression $[(p \vee q) \wedge (q$ $\rightarrow r) \wedge (\sim r)]$ $\rightarrow (p \wedge q)$ is False,then the truth values of $p, q, r$ are respectively:

Similar Questions

Identify the quantifier in the following statement and write the negation of the statement.
For every real number $x, x$ is less than $x+1.$

The given circuit is equivalent to:

$p$ and $q$ are two logical statements. If $r: p \rightarrow (\sim p \vee q)$ has truth value false,then the truth values of $p$ and $q$ are respectively:

Consider the following statements:
$r$: If $p \to q$ is false then $p \lor q$ is false.
$s$: If $p \leftrightarrow q$ is false then $p \lor q$ is false.
The truth values of $r \to s$ and $s \to r$ are respectively . . . . . .

The negation of the statement pattern $p \vee (q \rightarrow \sim r)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module