If the value of the discriminant of the quadr | vedclass

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(B) The standard form of a quadratic equation is $ax^{2}+bx+c=0$. Comparing $x^{2}-10x+(2k-1)=0$ with the standard form,we get $a=1$,$b=-10$,and $c=2k

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(B) The standard form of a quadratic equation is $ax^{2}+bx+c=0$. Comparing $x^{2}-10x+(2k-1)=0$ with the standard form,we get $a=1$,$b=-10$,and $c=2k-1$.The discriminant $D$ is given by the formula $D = b^{2}-4ac$.Given that $D = 40$,we substitute the values into the formula:$(-10)^{2} - 4(1)(2k-1) = 40$$100 - 4(2k-1) = 40$Subtract $100$ from both sides:$-4(2k-1) = 40 - 100$$-4(2k-1) = -60$Divide by $-4$:$2k-1 = 15$Add $1$ to both sides:$2k = 16$Divide by $2$:$k = 8$.

If the value of the discriminant of the quadratic equation $x^{2}-10x+(2k-1)=0$ is $40$,then $k = \ldots$.

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