If the vertex of the conic $y^{2}-4y=4x-4a$ always lies between the straight lines $x+y=3$ and $2x+2y-1=0$, then:

  • A
    $2 < a < 4$
  • B
    $-\frac{1}{2} < a < 2$
  • C
    $0 < a < 2$
  • D
    $-\frac{1}{2} < a < \frac{3}{2}$

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