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Question

(A) The energy $E$ of a photon is given by $E = h 
u = \frac{hc}{\lambda}$.Given: $\lambda = 2000 \ 	ext{Å} = 2000 	imes 10^{-8} \ 	ext{cm} = 2

Vedclass · Accepted Answer

$9.94 	imes 10^{-12}$

Vedclass · Answer

(A) The energy $E$ of a photon is given by $E = h 
u = \frac{hc}{\lambda}$.Given: $\lambda = 2000 \ 	ext{Å} = 2000 	imes 10^{-8} \ 	ext{cm} = 2 	imes 10^{-5} \ 	ext{cm}$.Speed of light $c = 3 	imes 10^{10} \ 	ext{cm/s}$.Planck's constant $h = 6.626 	imes 10^{-27} \ 	ext{erg} \cdot 	ext{s}$.Frequency $
u = \frac{c}{\lambda} = \frac{3 	imes 10^{10}}{2 	imes 10^{-5}} = 1.5 	imes 10^{15} \ 	ext{s}^{-1}$.Energy $E = h 
u = (6.626 	imes 10^{-27} \ 	ext{erg} \cdot 	ext{s}) 	imes (1.5 	imes 10^{15} \ 	ext{s}^{-1}) \approx 9.94 	imes 10^{-12} \ 	ext{erg}$.

If the wavelength of an electromagnetic radiation is $2000 \ \text{Å}$, what is its energy in ergs?

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