(A) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{\max}$ is given by:$K_{\max} = h\nu - W_0$Where:$h = 6.63 \times 10^

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(A) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{\max}$ is given by:$K_{\max} = h\nu - W_0$Where:$h = 6.63 \times 10^{-34} \ J \cdot s$ (Planck's constant)$\nu = 8 \times 10^{14} \ Hz$ (Frequency of incident light)$W_0 = 3.2 \times 10^{-19} \ J$ (Work function of the metal)Substituting the values:$K_{\max} = (6.63 \times 10^{-34} \times 8 \times 10^{14}) - 3.2 \times 10^{-19}$$K_{\max} = (53.04 \times 10^{-20}) - 3.2 \times 10^{-19}$$K_{\max} = 5.304 \times 10^{-19} - 3.2 \times 10^{-19}$$K_{\max} = 2.104 \times 10^{-19} \ J$Therefore,the correct option is $A$.

Class 12 Physics Dual Nature of Radiation and Matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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If the work function for a certain metal is $3.2 \times 10^{-19} \ J$ and it is illuminated with light of frequency $8 \times 10^{14} \ Hz$,the maximum kinetic energy of the photo-electrons would be (given $h = 6.63 \times 10^{-34} \ J \cdot s$):

A
$2.104 \times 10^{-19} \ J$
B
$8.5 \times 10^{-19} \ J$
C
$5.3 \times 10^{-19} \ J$
D
$3.2 \times 10^{-19} \ J$

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Dual Nature of Radiation and Matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

The work function of caesium is $2.14 \ eV$. Find the wavelength of the incident light if the photocurrent is brought to zero by a stopping potential of $0.60 \ V$. (Answer in $nm$)

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The maximum velocity of photoelectrons emitted from a metal surface is $1.2 \times 10^6 \ m/s$. If the specific charge of the electron is $1.8 \times 10^{11} \ C/kg$,then the value of the stopping potential in volts is:

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Maximum velocity of photoelectrons emitted by a metal surface is $1.2 \times 10^6\, m/s$. Assuming the specific charge of the electron to be $1.8 \times 10^{11}\, C/kg$,the value of the stopping potential in volt will be

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Which one of the following graphs correctly represents the variation of maximum kinetic energy $(E_{k})$ of the emitted electrons with frequency $(\nu)$ of incident light in the photoelectric effect?

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When light of frequency twice the threshold frequency is incident on a metal plate,the maximum velocity of the emitted electron is $v_{1}$. When the frequency of incident radiation is increased to five times the threshold value,the maximum velocity of the emitted electron becomes $v_{2}$. If $v_{2} = x v_{1}$,the value of $x$ will be...........

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If the work function for a certain metal is $3.2 \times 10^{-19} \ J$ and it is illuminated with light of frequency $8 \times 10^{14} \ Hz$,the maximum kinetic energy of the photo-electrons would be (given $h = 6.63 \times 10^{-34} \ J \cdot s$):

Similar Questions

The work function of caesium is $2.14 \ eV$. Find the wavelength of the incident light if the photocurrent is brought to zero by a stopping potential of $0.60 \ V$. (Answer in $nm$)

The maximum velocity of photoelectrons emitted from a metal surface is $1.2 \times 10^6 \ m/s$. If the specific charge of the electron is $1.8 \times 10^{11} \ C/kg$,then the value of the stopping potential in volts is:

Maximum velocity of photoelectrons emitted by a metal surface is $1.2 \times 10^6\, m/s$. Assuming the specific charge of the electron to be $1.8 \times 10^{11}\, C/kg$,the value of the stopping potential in volt will be

Which one of the following graphs correctly represents the variation of maximum kinetic energy $(E_{k})$ of the emitted electrons with frequency $(\nu)$ of incident light in the photoelectric effect?

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