(A) According to Einstein's photoelectric equation: $h\nu = h\nu_{0} + K_{\text{max}}$,where $K_{\text{max}} = \frac{1}{2}mv^{2}$.Case $1$: When $\nu

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) According to Einstein's photoelectric equation: $h\nu = h\nu_{0} + K_{\text{max}}$,where $K_{\text{max}} = \frac{1}{2}mv^{2}$.Case $1$: When $\nu = 2\nu_{0}$:$h(2\nu_{0}) = h\nu_{0} + \frac{1}{2}mv_{1}^{2}$$h\nu_{0} = \frac{1}{2}mv_{1}^{2} \dots(1)$Case $2$: When $\nu = 5\nu_{0}$:$h(5\nu_{0}) = h\nu_{0} + \frac{1}{2}mv_{2}^{2}$$4h\nu_{0} = \frac{1}{2}mv_{2}^{2} \dots(2)$Dividing equation $(2)$ by $(1)$:$\frac{4h\nu_{0}}{h\nu_{0}} = \frac{\frac{1}{2}mv_{2}^{2}}{\frac{1}{2}mv_{1}^{2}}$$4 = \left(\frac{v_{2}}{v_{1}}\right)^{2}$$\frac{v_{2}}{v_{1}} = \sqrt{4} = 2$$v_{2} = 2v_{1}$Given $v_{2} = xv_{1}$,therefore $x = 2$.

Class 12 Physics Dual Nature of Radiation and Matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

Medium

When light of frequency twice the threshold frequency is incident on a metal plate,the maximum velocity of the emitted electron is $v_{1}$. When the frequency of incident radiation is increased to five times the threshold value,the maximum velocity of the emitted electron becomes $v_{2}$. If $v_{2} = x v_{1}$,the value of $x$ will be...........

JEE MAIN 2022 All JEE MAIN

A
$2$
B
$4$
C
$8$
D
$16$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Dual Nature of Radiation and Matter

Subtopic

Einstein's Photoelectric Equation and Energy Quantum of Radiation

Previous Year

JEE MAIN 2022 Paper All JEE MAIN years →

The work function of caesium is $2.14\, eV$. Find the wavelength of the incident light if the photo current is brought to zero by a stopping potential of $0.60\, V$. (Result in $nm$)

Medium

View Solution

When light of wavelength $300 \; nm$ falls on a photoelectric emitter,photoelectrons are liberated. For another emitter,light of $600 \; nm$ wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

MediumAIPMT 1993

View Solution

In the photoelectric effect,when photons of energy $h \nu$ fall on a photosensitive surface (work function $h \nu_0$),electrons are emitted from the metallic surface. It is possible to say that:

Easy

View Solution

If the work function for a certain metal is $3.2 \times 10^{-19} \ J$ and it is illuminated with light of frequency $8 \times 10^{14} \ Hz$,the maximum kinetic energy of the photo-electrons would be (given $h = 6.63 \times 10^{-34} \ J \cdot s$):

Medium

View Solution

For a photosensitive material, the work function is $W_0$ and the stopping potential is $V$. What is the wavelength of the incident radiation? ($h$ = Planck's constant, $c$ = velocity of light, $e$ = electronic charge)

MediumMHT CET 2026

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

The work function of caesium is $2.14\, eV$. Find the wavelength of the incident light if the photo current is brought to zero by a stopping potential of $0.60\, V$. (Result in $nm$)

When light of wavelength $300 \; nm$ falls on a photoelectric emitter,photoelectrons are liberated. For another emitter,light of $600 \; nm$ wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

In the photoelectric effect,when photons of energy $h \nu$ fall on a photosensitive surface (work function $h \nu_0$),electrons are emitted from the metallic surface. It is possible to say that:

If the work function for a certain metal is $3.2 \times 10^{-19} \ J$ and it is illuminated with light of frequency $8 \times 10^{14} \ Hz$,the maximum kinetic energy of the photo-electrons would be (given $h = 6.63 \times 10^{-34} \ J \cdot s$):

For a photosensitive material, the work function is $W_0$ and the stopping potential is $V$. What is the wavelength of the incident radiation? ($h$ = Planck's constant, $c$ = velocity of light, $e$ = electronic charge)

Vedclass Test Series

Exam Paper Generator

Online Exam Module