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(B) The correct answer is $B$.In the Geiger-Marsden experiment,the objective is to target $\alpha$-particles towards an atom to observe their scatteri

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highly malleable

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(B) The correct answer is $B$.In the Geiger-Marsden experiment,the objective is to target $\alpha$-particles towards an atom to observe their scattering.This experiment requires a target that is extremely thin,ideally only a few atoms thick,to ensure that the $\alpha$-particles undergo minimal scattering events.Gold is known for being highly malleable,which allows it to be beaten into an extremely thin foil (a few micrometers thick). This physical property made it the ideal material for Rutherford's experiment.

In $1911$,the physicist Ernest Rutherford discovered that atoms have a tiny,dense nucleus by shooting positively charged particles at a very thin gold foil. $A$ key physical property which led Rutherford to use gold was that it was

Similar Questions

Calculate the number of atoms in $39.4$ $g$ of gold. The molar mass of gold is $197$ $g$ $mol^{-1}$.

An $\alpha$-particle of $5 \; MeV$ energy strikes a stationary uranium nucleus at a scattering angle of $180^o$. The distance of closest approach of the $\alpha$-particle to the nucleus will be of the order of:

The graph which depicts the results of the Rutherford gold foil experiment with $\alpha$-particles is:
$\theta$: Scattering angle
$Y$: Number of scattered $\alpha$-particles detected
(Plots are schematic and not to scale)

If in Rutherford's experiment,the number of particles scattered at $90^o$ angle are $28$ per min,then the number of scattered particles at an angle $60^o$ and $120^o$ will be:

Find the number of atoms in $39.4 \ g$ of gold. The molar mass of gold is $197 \ g \ mol^{-1}$.

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