In BrF_3 molecule,the lone pairs occupy equat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In $BrF_3$,the central atom $Br$ has $7$ valence electrons. It forms $3$ $Br-F$ bonds and has $2$ lone pairs,resulting in a total of $5$ electron

Vedclass · Accepted Answer

Lone pair-lone pair repulsion and lone pair-bond pair repulsion

Vedclass · Answer

(A) In $BrF_3$,the central atom $Br$ has $7$ valence electrons. It forms $3$ $Br-F$ bonds and has $2$ lone pairs,resulting in a total of $5$ electron pairs ($sp^3d$ hybridization).According to $VSEPR$ theory,lone pairs prefer equatorial positions in a trigonal bipyramidal geometry to minimize lone pair-lone pair repulsion and lone pair-bond pair repulsion.By placing both lone pairs in equatorial positions,the $90^{\circ}$ lone pair-lone pair interactions are avoided,which significantly reduces the overall repulsion in the molecule.

In $BrF_3$ molecule,the lone pairs occupy equatorial positions to minimize

Similar Questions

Identify the molecule which contains a lone pair of electrons on the sulphur atom.

According to $VSEPR$ theory,in which species do all the atoms lie in the same plane?
$1.$ $CH^{+}_3$
$2.$ $CH^{-}_3$

What is the shape of bromine pentafluoride?

Which of the following is the correct decreasing order of bond angles?

Which set of species is arranged in order of increasing $O-N-O$ bond angle?

Vedclass Test Series

Exam Paper Generator

Online Exam Module