In $YDSE$,let $S_1$ and $S_2$ be the two slits,and $C$ be the centre of the screen. If $\angle S_1 C S_2 = \theta$ and $\lambda$ is the wavelength,the fringe width is

  • A
    $\frac{\lambda}{\theta}$
  • B
    $\lambda \theta$
  • C
    $\frac{2\lambda}{\theta}$
  • D
    $\frac{\lambda}{2\theta}$

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