In an $n-p-n$ transistor circuit,the collector current is $10 \, mA$. If $90 \%$ of the electrons reach the collector,then the emitter current will be:

  • A
    $1 \, mA$
  • B
    $0.1 \, mA$
  • C
    $2 \, mA$
  • D
    nearly $11 \, mA$

Explore More

Similar Questions

An $n-p-n$ transistor can be considered to be equivalent to two diodes connected back-to-back. Which of the following figures is the correct one?

In a $CE$ transistor,when the base current increases by $60 \mu A$,the change in base-emitter voltage is $1.2 \ V$. Then the input resistance is: (in $\Omega$)

In a transistor amplifier, a change of $0.2 \text{ mA}$ in the base current causes a change of $5 \text{ mA}$ in the collector current. If input resistance is $2 \text{ k}\Omega$ and voltage gain is $75$, the load resistance used in the circuit is

In $n-p-n$ transistor, in $CE$ configuration:

In the circuit shown in the figure,when the input voltage $V_i$ is $10\, V$,$V_{BE}$ is zero and $V_{CE}$ is also zero. Find the values of $I_B$,$I_C$,and $\beta$.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo