In Delta ABC,if angle A angle B,then AC ldo | vedclass

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(B) In any triangle,the side opposite to the larger angle is longer than the side opposite to the smaller angle.Given that $\angle A > \angle B$ in $\

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(B) In any triangle,the side opposite to the larger angle is longer than the side opposite to the smaller angle.Given that $\angle A > \angle B$ in $\Delta ABC$.The side opposite to $\angle A$ is $BC$.The side opposite to $\angle B$ is $AC$.Since $\angle A > \angle B$,it follows that the side opposite to $\angle A$ must be greater than the side opposite to $\angle B$.Therefore,$BC > AC$,which is equivalent to $AC < BC$.

In $\Delta ABC$,if $\angle A > \angle B$,then $AC \ldots \ldots BC$.

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