In Delta ABC,mangle B = 90^circ,mangle C = 30 | vedclass

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(A) In right-angled $\Delta ABC$,we are given the hypotenuse $AC = 30 	ext{ cm}$ and $\angle C = 30^\circ$.We need to find the side $AB$,which is opp

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(A) In right-angled $\Delta ABC$,we are given the hypotenuse $AC = 30 	ext{ cm}$ and $\angle C = 30^\circ$.We need to find the side $AB$,which is opposite to $\angle C$.Using the trigonometric ratio $\sin 	heta = \frac{	ext{opposite side}}{	ext{hypotenuse}}$:$\sin 30^\circ = \frac{AB}{AC}$Since $\sin 30^\circ = \frac{1}{2}$,we have:$\frac{1}{2} = \frac{AB}{30}$$AB = \frac{30}{2} = 15 	ext{ cm}$.

In $\Delta ABC$,$m\angle B = 90^\circ$,$m\angle C = 30^\circ$ and $AC = 30 \text{ cm}$,then $AB = \ldots \text{ cm}$.

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