In odot(O, r),the length of minor widehat{ACB | vedclass

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(B) The length of an arc is given by the formula $L = \frac{	heta}{360^{\circ}} 	imes 2\pi r$,where $	heta$ is the angle subtended at the centre.Gi

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(B) The length of an arc is given by the formula $L = \frac{	heta}{360^{\circ}} 	imes 2\pi r$,where $	heta$ is the angle subtended at the centre.Given that the length of minor $\widehat{ACB} = \frac{1}{6} 	imes 	ext{circumference}$.Since the circumference of the circle is $2\pi r$,we have:$\frac{	heta}{360^{\circ}} 	imes 2\pi r = \frac{1}{6} 	imes 2\pi r$Dividing both sides by $2\pi r$,we get:$\frac{	heta}{360^{\circ}} = \frac{1}{6}$$	heta = \frac{360^{\circ}}{6}$$	heta = 60^{\circ}$

In $\odot(O, r)$,the length of minor $\widehat{ACB}$ is $\frac{1}{6}$ times the circumference of the circle. Then,the measure of the angle subtended at the centre by minor $\widehat{ACB}$ is ......... (in $^{\circ}$)

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