In SHM,the acceleration versus displacement ( | vedclass

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(A) The acceleration $a$ of a particle in $SHM$ is given by the equation $a = -\omega^{2}x$,where $\omega$ is the angular frequency and $x$ is the dis

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is always a straight line passing through the origin with a negative slope.

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(A) The acceleration $a$ of a particle in $SHM$ is given by the equation $a = -\omega^{2}x$,where $\omega$ is the angular frequency and $x$ is the displacement from the mean position.Comparing this with the equation of a straight line $y = mx + c$,we see that $y = a$,$m = -\omega^{2}$,$x = x$,and $c = 0$.Since the intercept $c$ is $0$,the graph is a straight line passing through the origin.Since $\omega^{2}$ is always positive,the slope $m = -\omega^{2}$ is always negative.Therefore,the graph is a straight line passing through the origin with a negative slope.

In $SHM$,the acceleration versus displacement (from mean position) graph:

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