In a $p-n-p$ transistor, the collector current is

$A$ common emitter circuit is used as an amplifier with a current gain of $50$. If the input resistance is $1 \ k\Omega$ and the input voltage is $5 \ V$, then the output current is ....... $mA$.

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

For a given transistor,if $\alpha = 0.95$,find the common emitter current gain $\beta$.

In an amplifier circuit,the value of the load resistance $R_L$ is $2 \text{ k}\Omega$. $A$ change of $10 \text{ }\mu\text{A}$ in the base current of the transistor results in a change of $1 \text{ mA}$ in the collector current. The change in the collector-emitter voltage $(V_{CE})$ is ....... $V$.

In the following common emitter circuit, if $\beta=100$, $V_{CE}=7 \, V$, $V_{BE}$ is negligible, and $R_C=2 \, k\Omega$, then $I_B=$ (in $\, mA$)?