In a body-centred cubic $(bcc)$ lattice of potassium, the correct relation between the atomic radius $(r)$ of potassium and the edge-length $(a)$ of the cube is:
- A$r = \frac{a}{\sqrt{2}}$
- B$r = \frac{a}{\sqrt{3}}$
- C$r = \frac{\sqrt{3}}{2} a$
- D$r = \frac{\sqrt{3}}{4} a$
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