In a cell,the following reactions take place:
$Fe^{2+} \rightarrow Fe^{3+} + e^{-}$ $\quad$ $E^{\circ}_{Fe^{3+} / Fe^{2+}} = 0.77 \, V$
$2I^{-} \rightarrow I_{2} + 2e^{-}$ $\quad$ $E^{\circ}_{I_{2} / I^{-}} = 0.54 \, V$
The standard electrode potential for the spontaneous reaction in the cell is $x \times 10^{-2} \, V$ at $298 \, K$. The value of $x$ is .... (Nearest Integer)

  • A
    $95$
  • B
    $202$
  • C
    $23$
  • D
    $4$

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Similar Questions

Standard reduction potentials of the half-reactions are given below:
$F_{2(g)} + 2e^- \rightarrow 2F^-_{(aq)}$; $E^o = +2.85 \ V$
$Cl_{2(g)} + 2e^- \rightarrow 2Cl^-_{(aq)}$; $E^o = +1.36 \ V$
$Br_{2(l)} + 2e^- \rightarrow 2Br^-_{(aq)}$; $E^o = +1.06 \ V$
$I_{2(s)} + 2e^- \rightarrow 2I^-_{(aq)}$; $E^o = +0.53 \ V$
The strongest oxidising and reducing agents respectively are:

Which of the following metals behaves as the weakest reducing agent?
$E^\circ_{(\text{Li}^+/\text{Li})} = -3.05 \text{ V}$, $E^\circ_{(\text{Au}^{3+}/\text{Au})} = 1.40 \text{ V}$, $E^\circ_{(\text{Ag}^+/\text{Ag})} = 0.80 \text{ V}$, $E^\circ_{(\text{Mg}^{2+}/\text{Mg})} = -2.36 \text{ V}$

Given below are the half-cell reactions: $Mn^{2+} + 2e^- \rightarrow Mn$ $(E^0 = -1.18 \text{ V})$; $Mn^{3+} + e^- \rightarrow Mn^{2+}$ $(E^0 = +1.51 \text{ V})$. The $E^0_{cell}$ for $3Mn^{2+} \rightarrow Mn + 2Mn^{3+}$ will be . . . . . .

The standard electrode potentials $E^{\circ} (V)$ for $Li^{+} / Li$ and $Na^{+} / Na$ respectively are:

Which is the increasing order of reducing power of the following metals on the basis of standard electrode potential? $Ag^{+}/Ag = 0.80 \ V$,$Mg^{2+}/Mg = -2.37 \ V$,$Hg^{2+}/Hg = 0.79 \ V$,$Cr^{3+}/Cr = -0.74 \ V$

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