In a cell that utilises the reaction $Zn_{(s)} + 2H^{+}_{(aq)} \to Zn^{2+}_{(aq)} + H_{2_{(g)}}$,addition of $H_2SO_4$ to the cathode compartment will:
- AIncrease the $E_{cell}$ and shift equilibrium to the right
- BLower the $E_{cell}$ and shift equilibrium to the right
- CLower the $E_{cell}$ and shift equilibrium to the left
- DIncrease the $E_{cell}$ and shift equilibrium to the left
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Similar Questions
The $emf$ of the following three galvanic cells:
$1. Zn|Zn^{2+} (1 \ M)||Cu^{2+} (1 \ M)|Cu$
$2. Zn|Zn^{2+} (0.1 \ M)||Cu^{2+} (1 \ M)|Cu$
$3. Zn|Zn^{2+} (1 \ M)||Cu^{2+} (0.1 \ M)|Cu$
are represented by $E_1, E_2, E_3$. Which of the following statements is true?
$1. Zn|Zn^{2+} (1 \ M)||Cu^{2+} (1 \ M)|Cu$
$2. Zn|Zn^{2+} (0.1 \ M)||Cu^{2+} (1 \ M)|Cu$
$3. Zn|Zn^{2+} (1 \ M)||Cu^{2+} (0.1 \ M)|Cu$
are represented by $E_1, E_2, E_3$. Which of the following statements is true?
Medium
View SolutionWhat will be the electrode potential of a $Cu$ electrode dipped in $0.025 \ M \ CuSO_4$ solution at $298 \ K$,given that the standard reduction potential of $Cu$ is $0.34 \ V$ (in $V$)?
Easy
View SolutionFor the cell,$Mn_{(s)} | Mn^{2+}_{(aq)} (0.4 \, M) || Sn^{2+}_{(aq)} (0.04 \, M) | Sn_{(s)}$,calculate the free energy change $(\Delta G)$ at $298 \, K$ in $kJ$. Given: $E^o_{Mn^{2+}/Mn} = -1.18 \, V$; $E^o_{Sn^{2+}/Sn} = -0.14 \, V$; $\frac{2.303RT}{F} = 0.06$.
Medium
View SolutionCalculate the cell potential for the following cell: ............... $V$
$Cr_{(s)} | Cr^{3+}_{(0.1 \, M)} || Fe^{2+}_{(0.01 \, M)} | Fe_{(s)}$
Given: $E^0_{Cr^{3+}|Cr} = -0.72 \, V$,$E^0_{Fe^{2+}|Fe} = -0.42 \, V$ (in $, V$)
$Cr_{(s)} | Cr^{3+}_{(0.1 \, M)} || Fe^{2+}_{(0.01 \, M)} | Fe_{(s)}$
Given: $E^0_{Cr^{3+}|Cr} = -0.72 \, V$,$E^0_{Fe^{2+}|Fe} = -0.42 \, V$ (in $, V$)
Easy
View SolutionFor the following electrochemical cell at $298 \ K$,
$Pt_{(s)} \mid H_2(g, 1 \ bar) \mid H^{+}(aq, 1 \ M) \parallel M^{4+}_{(aq)}, M^{2+}_{(aq)} \mid Pt_{(s)}$
$E_{\text{cell}} = 0.092 \ V$ when $\frac{[M^{2+}_{(aq)}]}{[M^{4+}_{(aq)}]} = 10^x$
Given : $E^0_{M^{4+}/M^{2+}} = 0.151 \ V$; $2.303 \frac{RT}{F} = 0.059 \ V$
The value of $x$ is
$Pt_{(s)} \mid H_2(g, 1 \ bar) \mid H^{+}(aq, 1 \ M) \parallel M^{4+}_{(aq)}, M^{2+}_{(aq)} \mid Pt_{(s)}$
$E_{\text{cell}} = 0.092 \ V$ when $\frac{[M^{2+}_{(aq)}]}{[M^{4+}_{(aq)}]} = 10^x$
Given : $E^0_{M^{4+}/M^{2+}} = 0.151 \ V$; $2.303 \frac{RT}{F} = 0.059 \ V$
The value of $x$ is
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