In a circle with radius 42 , cm,an arc subten | vedclass

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(A) Given: Radius $r = 42 \, cm$ and central angle $	heta = 120^{\circ}$.Length of the arc $l = \frac{	heta}{360^{\circ}} 	imes 2\pi r = \frac{120^

Vedclass · Accepted Answer

$88 \, cm, 1848 \, cm^2$

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(A) Given: Radius $r = 42 \, cm$ and central angle $	heta = 120^{\circ}$.Length of the arc $l = \frac{	heta}{360^{\circ}} 	imes 2\pi r = \frac{120^{\circ}}{360^{\circ}} 	imes 2 	imes \frac{22}{7} 	imes 42 = \frac{1}{3} 	imes 2 	imes 22 	imes 6 = 88 \, cm$.Area of the sector $A = \frac{	heta}{360^{\circ}} 	imes \pi r^2 = \frac{120^{\circ}}{360^{\circ}} 	imes \frac{22}{7} 	imes 42 	imes 42 = \frac{1}{3} 	imes 22 	imes 6 	imes 42 = 22 	imes 2 	imes 42 = 1848 \, cm^2$.

In a circle with radius $42 \, cm$,an arc subtends an angle of $120^{\circ}$ at the centre. Find the length of this arc and the area of the sector formed by this arc.

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