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(D) Let $M$,$P$,and $C$ represent the sets of students studying Mathematics,Physics,and Chemistry respectively.Given: $n(M) = 23, n(P) = 24, n(C) = 19

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$22$

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(D) Let $M$,$P$,and $C$ represent the sets of students studying Mathematics,Physics,and Chemistry respectively.Given: $n(M) = 23, n(P) = 24, n(C) = 19$.$n(M \cap P) = 12, n(M \cap C) = 9, n(P \cap C) = 7$.$n(M \cap P \cap C) = 4$.The number of students studying exactly one subject is given by:$n(	ext{Only } M) = n(M) - n(M \cap P) - n(M \cap C) + n(M \cap P \cap C) = 23 - 12 - 9 + 4 = 6$.$n(	ext{Only } P) = n(P) - n(P \cap M) - n(P \cap C) + n(P \cap M \cap C) = 24 - 12 - 7 + 4 = 9$.$n(	ext{Only } C) = n(C) - n(C \cap M) - n(C \cap P) + n(C \cap M \cap P) = 19 - 9 - 7 + 4 = 7$.Total number of students who have taken exactly one subject $= 6 + 9 + 7 = 22$.

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