In a common emitter amplifier configuration, the current gain is $62$. The collector resistance and input resistance are $5 \text{ k}\Omega$ and $500 \text{ }\Omega$ respectively. If the input voltage is $0.01 \text{ V}$, the output voltage will be (in $V$)

$A$ common-emitter amplifier is designed with a $n-p-n$ transistor $(\alpha = 0.99)$. The input impedance is $1\, k\Omega$ and load is $10\, k\Omega$. The voltage gain will be

An $NPN$ transistor is used in common emitter configuration as an amplifier with $1\,k\Omega$ load resistance. $A$ signal voltage of $10\,mV$ is applied across the base-emitter. This produces a $3\,mA$ change in the collector current and $15\,\mu A$ change in the base current of the amplifier. The input resistance and voltage gain are:

In common emitter mode of a transistor, the d.c. current gain $(\beta)$ is $20$ and the emitter current $(I_E)$ is $7 \text{ mA}$. The collector current $(I_C)$ is: (in $/3 \text{ mA}$)

In the following common emitter circuit,$\beta=100$ and $V_{CE}=7 \text{ V}$. If $V_{BE}$ is negligible,then the base current is (in $\text{ mA}$)

The correct relation between $\alpha$ (ratio of collector current to emitter current) and $\beta$ (ratio of collector current to base current) of a transistor is :