In a common emitter configuration, a transistor has $\beta=50$ and input resistance $1 \text{ k}\Omega$. If the peak value of a.c. input is $0.01 \text{ V}$, then the peak value of collector current is: (in $\mu\text{A}$)

$A$ common emitter transistor amplifier is connected with a load resistance of $6 k\Omega$. When a small a.c. signal of $15 mV$ is added to the base-emitter voltage, the alternating base current is $20 \mu A$ and the alternating collector current is $1.8 mA$. What is the voltage gain of the amplifier?

In a $CE$ circuit,the collector of a transistor is kept at a constant voltage $V_C = 1.5 \ V$. When the base current changes from $100 \ \mu A$ to $150 \ \mu A$,the collector current changes from $5 \ mA$ to $10 \ mA$. The current gain $\beta$ for this transistor is:

An $n-p-n$ transistor power amplifier in $C-E$ configuration gives

For a common-emitter transistor amplifier, the current gain is $60$. If the emitter current is $6.6 \,mA$, then its base current is (in $\,mA$)

Input signal to a common emitter amplifier having a voltage gain of $1000$ is given by $v_i = (0.004 \, V) \sin(\omega t + \pi/2)$. The corresponding output signal is