For a common-emitter transistor amplifier, th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a common-emitter configuration, the current gain $\beta$ is defined as $\beta = \frac{I_C}{I_B}$.Given $\beta = 60$, we have $I_C = 60 I_B$.We

Vedclass · Accepted Answer

$0.108$

Vedclass · Answer

(B) In a common-emitter configuration, the current gain $\beta$ is defined as $\beta = \frac{I_C}{I_B}$.Given $\beta = 60$, we have $I_C = 60 I_B$.We know that the emitter current $I_E$ is the sum of the base current $I_B$ and the collector current $I_C$:$I_E = I_B + I_C$Substituting $I_C = 60 I_B$ into the equation:$I_E = I_B + 60 I_B = 61 I_B$Given $I_E = 6.6 \,mA$, we can solve for $I_B$:$6.6 \,mA = 61 I_B$$I_B = \frac{6.6}{61} \,mA \approx 0.108 \,mA$.

For a common-emitter transistor amplifier, the current gain is $60$. If the emitter current is $6.6 \,mA$, then its base current is (in $\,mA$)

Similar Questions

For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

The symbol given below represents:

Three circuit connections of a $PNP$ transistor are given below. Which of the following represents the Common-Emitter configuration?

The correct relation between $\alpha$ (ratio of collector current to emitter current) and $\beta$ (ratio of collector current to base current) of a transistor is :

Vedclass Test Series

Exam Paper Generator

Online Exam Module