The symbol given below represents:

What is the voltage gain of a common-emitter amplifier with an input resistance of $3 \ \Omega$ and a load resistance of $24 \ \Omega$? (Given $\beta = 6$)

In an $n-p-n$ transistor amplifier,the collector current is $9 \ mA$. If $90 \%$ of the electrons emitted reach the collector,then

If the base current is $100 \mu A$ and the collector current is $3 \ mA$,then the values of $\beta$,$\alpha$,and $I_e$ are respectively:

The dc common emitter current gain of an $n-p-n$ transistor is $50$. The potential difference applied across the collector and emitter of a transistor used in $CE$ configuration is $V_{CE} = 2 \ V$. If the collector resistance $R_{C} = 4 \ k\Omega$,the base current $(I_{B})$ and the collector current $(I_{C})$ are:

In a common emitter configuration with suitable bias,it is given that $R_L$ is the load resistance and $R_{BE}$ is the small signal dynamic resistance (input side). Then,the voltage gain,current gain,and power gain are given,respectively,by: [$\beta$ is the current gain,$I_B$,$I_C$,$I_E$ are respectively base,collector,and emitter currents]