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(B) According to Bohr's postulate,the angular momentum $L$ of an electron in the $n^{	ext{th}}$ orbit is given by $L = \frac{nh}{2\pi}$.For the $5^{\

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$\frac{h}{\pi}$

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(B) According to Bohr's postulate,the angular momentum $L$ of an electron in the $n^{	ext{th}}$ orbit is given by $L = \frac{nh}{2\pi}$.For the $5^{	ext{th}}$ orbit $(n_1 = 5)$,the angular momentum is $L_5 = \frac{5h}{2\pi}$.For the $3^{	ext{rd}}$ orbit $(n_2 = 3)$,the angular momentum is $L_3 = \frac{3h}{2\pi}$.The change in angular momentum $\Delta L$ is given by:$\Delta L = L_5 - L_3$$\Delta L = \frac{5h}{2\pi} - \frac{3h}{2\pi}$$\Delta L = \frac{h}{2\pi} (5 - 3)$$\Delta L = \frac{2h}{2\pi} = \frac{h}{\pi}$.

In a hydrogen atom,an electron makes a transition from the $5^{\text{th}}$ orbit to the $3^{\text{rd}}$ orbit. The change in the angular momentum for this electron is . . . . . . .

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