In any Bohr orbit of the hydrogen atom,the ra | vedclass

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(C) According to Bohr's model for a hydrogen-like atom,the kinetic energy $(K.E.)$ of an electron in an orbit of radius $r$ is given by $K.E. = \frac{

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$-0.5$

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(C) According to Bohr's model for a hydrogen-like atom,the kinetic energy $(K.E.)$ of an electron in an orbit of radius $r$ is given by $K.E. = \frac{kZe^2}{2r}$.The potential energy $(P.E.)$ of the electron in the same orbit is given by $P.E. = -\frac{kZe^2}{r}$.To find the ratio of kinetic energy to potential energy,we divide the two expressions:$\frac{K.E.}{P.E.} = \frac{\frac{kZe^2}{2r}}{-\frac{kZe^2}{r}} = -\frac{1}{2} = -0.5$.Thus,the ratio is $-0.5$.

In any Bohr orbit of the hydrogen atom,the ratio of kinetic energy to potential energy of the electron is

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