In a junction transistor, the collector current changes by $6.8 \,mA$, if the emitter current is changed by $7 \,mA$. For such a transistor, the current amplification factor is

In the figure,given that $V_{BB}$ supply can vary from $0$ to $5.0 \,V$,$V_{CC} = 5\,V$,$\beta_{dc} = 200$,$R_B = 100\,k\Omega$,$R_C = 1\,k\Omega$ and $V_{BE} = 1.0\,V$. The minimum base current and the input voltage at which the transistor will go to saturation,will be respectively:

In a $NPN$ transistor,the collector current is $24 \, mA$. If $80\%$ of electrons reach the collector,what is the base current in $mA$?

In common emitter mode of a transistor, the d.c. current gain $(\beta)$ is $20$ and the emitter current $(I_E)$ is $7 \text{ mA}$. The collector current $(I_C)$ is: (in $/3 \text{ mA}$)

$A$ transistor has a current amplification factor of $60$. In a $CE$ amplifier, input resistance is $1 \, k\Omega$ and output voltage is $0.01 \, V$. The transconductance is (in $SI$ units)

In a transistor circuit,the emitter-base circuit of a $n-p-n$ transistor is always