In a Linear Programming Problem (L.P.P.), the | vedclass

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(B) Step $1$: Identify the lines corresponding to the constraints: $L_1: 3x - y = 6$, $L_2: x = 3$, $L_3: y = 2$, $L_4: y = 0$, $L_5: x = 0$.Step $2$:

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$(\frac{8}{3}, 2), (3, 2), (3, 0), (2, 0)$

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(B) Step $1$: Identify the lines corresponding to the constraints: $L_1: 3x - y = 6$, $L_2: x = 3$, $L_3: y = 2$, $L_4: y = 0$, $L_5: x = 0$.Step $2$: Find the intersection points of these lines that satisfy all inequalities.- Intersection of $L_1$ and $L_4$ $(y=0)$: $3x - 0 = 6 \implies x = 2$. Point: $(2, 0)$.- Intersection of $L_1$ and $L_3$ $(y=2)$: $3x - 2 = 6 \implies 3x = 8 \implies x = 8/3$. Point: $(8/3, 2)$.- Intersection of $L_2$ and $L_3$ $(x=3, y=2)$: Point: $(3, 2)$.- Intersection of $L_2$ and $L_4$ $(x=3, y=0)$: Point: $(3, 0)$.Step $3$: The feasible region is bounded by the vertices $(2, 0), (8/3, 2), (3, 2),$ and $(3, 0)$.

In a Linear Programming Problem ($L$.$P$.$P$.), the corner points of the feasible region defined by the constraints $3x - y \geq 6$, $x \leq 3$, $y \leq 2$, $y \geq 0$, and $x \geq 0$ are:

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