In a nuclear reactor,the fuel is consumed at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The rate of mass consumption is given by $\frac{\Delta m}{\Delta t} = 1 	imes 10^{-3} 	ext{ g s}^{-1} = 10^{-6} 	ext{ kg s}^{-1}$.According to

Vedclass · Accepted Answer

$9 	imes 10^7$

Vedclass · Answer

(B) The rate of mass consumption is given by $\frac{\Delta m}{\Delta t} = 1 	imes 10^{-3} 	ext{ g s}^{-1} = 10^{-6} 	ext{ kg s}^{-1}$.According to Einstein's mass-energy equivalence principle,the power $P$ generated is given by $P = \frac{\Delta E}{\Delta t} = \left(\frac{\Delta m}{\Delta t}ight) c^2$.Substituting the values,where $c = 3 	imes 10^8 	ext{ m s}^{-1}$:$P = 10^{-6} 	ext{ kg s}^{-1} 	imes (3 	imes 10^8 	ext{ m s}^{-1})^2$.$P = 10^{-6} 	imes 9 	imes 10^{16} 	ext{ W}$.$P = 9 	imes 10^{10} 	ext{ W}$.Since $1 	ext{ kW} = 10^3 	ext{ W}$,we convert the power to kW:$P = \frac{9 	imes 10^{10}}{10^3} 	ext{ kW} = 9 	imes 10^7 	ext{ kW}$.

In a nuclear reactor,the fuel is consumed at the rate of $1 \times 10^{-3} \text{ g s}^{-1}$. The power generated in kW is

Similar Questions

The energy released when one nucleus of ${ }_{92} U^{235}$ undergoes fission is $188 MeV$. The energy released when $100 g$ of ${ }_{92} U^{235}$ undergoes fission is:

The Sun radiates energy continuously and maintains its brightness because:

The radiant energy from a red giant star is produced by:

If $200 \text{ MeV}$ of energy is released in the fission of one nucleus of ${ }_{92}^{236} U$, the number of nuclei that must undergo fission to release an energy of $1000 \text{ J}$ is

In the nuclear fission of one nucleus of $U^{235}$, the energy released is $188 \text{ MeV}$. The energy released in the nuclear fission of $235 \text{ g}$ of $U^{235}$ is nearly (Avogadro number $= 6.02 \times 10^{23} \text{ mol}^{-1}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module