(A) In a parabola spectrograph,the deflection $x$ of an ion is inversely proportional to the square of its velocity,i.e.,$x \propto \frac{1}{v^2}$.Thi

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(A) In a parabola spectrograph,the deflection $x$ of an ion is inversely proportional to the square of its velocity,i.e.,$x \propto \frac{1}{v^2}$.This means that the ion which experiences less deflection will have a higher velocity.From the given graph,the horizontal distances (deflections) of the ions $P, Q, R,$ and $S$ from the vertical axis are $x_1, x_2, x_3,$ and $x_4$ respectively.Observing the graph,we can see that $x_1 Since $v \propto \frac{1}{\sqrt{x}}$,it follows that $v_1 > v_2 > v_3 > v_4$.

Class 12 Physics Moving Charges and Magnetism Motion of Charged Particle In Magnetic Field

Medium

In a parabola spectrograph,the velocities of four positive ions $P, Q, R,$ and $S$ are $v_1, v_2, v_3,$ and $v_4$ respectively. Based on the provided parabola spectrograph image,determine the relationship between their velocities.

A
$v_1 > v_2 > v_3 > v_4$
B
$v_1 < v_2 < v_3 < v_4$
C
$v_1 = v_2 = v_3 = v_4$
D
$v_1 < v_2 > v_3 < v_4$

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Moving Charges and Magnetism

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Motion of Charged Particle In Magnetic Field

When an electron beam passes through an electric field,it gains kinetic energy. If the same beam passes through a magnetic field,then:

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$A$ particle with charge $q$,moving with a momentum $p$,enters a uniform magnetic field normally. The magnetic field has magnitude $B$ and is confined to a region of width $d$,where $d < \frac{p}{Bq}$. The particle is deflected by an angle $\theta$ in crossing the field.

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An electron has mass $9 \times 10^{-31} \ kg$ and charge $1.6 \times 10^{-19} \ C$ is moving with a velocity of $10^6 \ m/s$. It enters a region where a magnetic field exists. If it describes a circle of radius $0.10 \ m$,the intensity of the magnetic field must be:

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$A$ proton,a deuteron and an $\alpha$-particle having the same kinetic energy are moving in circular trajectories in a constant magnetic field. If ${r_p}$,${r_d}$ and ${r_\alpha}$ denote respectively the radii of the trajectories of these particles,then:

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An electron projected perpendicular to a uniform magnetic field $B$ moves in a circle. If Bohr's quantization is applicable,then the radius of the electronic orbit in the first excited state is $:$

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In a parabola spectrograph,the velocities of four positive ions $P, Q, R,$ and $S$ are $v_1, v_2, v_3,$ and $v_4$ respectively. Based on the provided parabola spectrograph image,determine the relationship between their velocities.

Similar Questions

When an electron beam passes through an electric field,it gains kinetic energy. If the same beam passes through a magnetic field,then:

$A$ particle with charge $q$,moving with a momentum $p$,enters a uniform magnetic field normally. The magnetic field has magnitude $B$ and is confined to a region of width $d$,where $d < \frac{p}{Bq}$. The particle is deflected by an angle $\theta$ in crossing the field.

An electron has mass $9 \times 10^{-31} \ kg$ and charge $1.6 \times 10^{-19} \ C$ is moving with a velocity of $10^6 \ m/s$. It enters a region where a magnetic field exists. If it describes a circle of radius $0.10 \ m$,the intensity of the magnetic field must be:

$A$ proton,a deuteron and an $\alpha$-particle having the same kinetic energy are moving in circular trajectories in a constant magnetic field. If ${r_p}$,${r_d}$ and ${r_\alpha}$ denote respectively the radii of the trajectories of these particles,then:

An electron projected perpendicular to a uniform magnetic field $B$ moves in a circle. If Bohr's quantization is applicable,then the radius of the electronic orbit in the first excited state is $:$

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