In a parallel plate capacitor,the separation | vedclass

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(C) The initial capacitance of the parallel plate capacitor with air is $C_0 = \frac{\epsilon_0 A}{d}$,where $d = 3\,mm$.When a dielectric slab of thi

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$3$

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(C) The initial capacitance of the parallel plate capacitor with air is $C_0 = \frac{\epsilon_0 A}{d}$,where $d = 3\,mm$.When a dielectric slab of thickness $t = 1\,mm$ and dielectric constant $K = 2$ is introduced,the new capacitance $C'$ is given by $C' = \frac{\epsilon_0 A}{d - t + \frac{t}{K}}$.To restore the original capacitance $C_0$,we must change the separation $d$ to a new value $d'$ such that the effective distance remains the same as the original air-filled capacitor.The effective distance $d_{eff} = d' - t + \frac{t}{K}$ must equal the original distance $d = 3\,mm$.Substituting the values: $d' - 1 + \frac{1}{2} = 3$.$d' - 0.5 = 3$.$d' = 3.5\,mm$.

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