In a plane electromagnetic wave,the electric field oscillates with a frequency $2 \times 10^{10} \,s^{-1}$ and amplitude $40 \,Vm^{-1}$. The energy density due to the electric field is (given $\varepsilon_0 = 8.85 \times 10^{-12} \,Fm^{-1}$):

  • A
    $1.52 \times 10^{-9} \,Jm^{-3}$
  • B
    $2.54 \times 10^{-19} \,Jm^{-3}$
  • C
    $3.54 \times 10^{-9} \,Jm^{-3}$
  • D
    $4.56 \times 10^{-9} \,Jm^{-3}$

Explore More

Similar Questions

$A$ light wave is travelling along the $y$-direction. If the corresponding $\vec E$ vector at any time is along the $x$-axis,the direction of the $\vec B$ vector at that time is along:

The electric field of a plane electromagnetic wave is given by $\overrightarrow{E} = E_{0}(\hat{x} + \hat{y}) \sin(kz - \omega t)$. Its magnetic field will be given by

The electromagnetic waves travel in a medium at a speed of $2.0 \times 10^{8} \ m/s$. The relative permeability of the medium is $1.0$. The relative permittivity of the medium will be (in $.25$)

The energy density associated with the electric field $\overrightarrow{E}$ and magnetic field $\overrightarrow{B}$ of an electromagnetic wave in free space is given by ($\epsilon_0$ - permittivity of free space,$\mu_0$ - permeability of free space):

If the amplitude of the magnetic field component of an electromagnetic wave in vacuum is $B_m = 510 \, nT$,then the amplitude of the electric field component of the wave is ......

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo