In a projectile motion,the velocity at maximu | vedclass

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Question

(B) In projectile motion,the velocity of the projectile can be resolved into two components: horizontal $(u_x = u \cos 	heta)$ and vertical $(u_y = u

Vedclass · Accepted Answer

$u \cos 	heta$

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(B) In projectile motion,the velocity of the projectile can be resolved into two components: horizontal $(u_x = u \cos 	heta)$ and vertical $(u_y = u \sin 	heta)$.At the maximum height,the vertical component of velocity becomes zero $(v_y = 0)$.However,the horizontal component of velocity remains constant throughout the motion because there is no acceleration acting in the horizontal direction.Therefore,the velocity at the maximum height is equal to the horizontal component,which is $u \cos 	heta$.

In a projectile motion,the velocity at maximum height is:

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