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(B) According to the principle of dimensional homogeneity,the argument of a trigonometric function must be dimensionless.Therefore,the dimensions of $

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$meter^{-1}, s^{-1}$

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(B) According to the principle of dimensional homogeneity,the argument of a trigonometric function must be dimensionless.Therefore,the dimensions of $k_1x$ and $k_2t$ must be $M^0 L^0 T^0$.For $k_1x$ to be dimensionless,the dimension of $k_1$ must be the inverse of the dimension of $x$ (distance).$[k_1] = [x]^{-1} = L^{-1}$. Thus,the unit of $k_1$ is $meter^{-1}$.For $k_2t$ to be dimensionless,the dimension of $k_2$ must be the inverse of the dimension of $t$ (time).$[k_2] = [t]^{-1} = T^{-1}$. Thus,the unit of $k_2$ is $s^{-1}$.Therefore,the units of $k_1$ and $k_2$ are $meter^{-1}$ and $s^{-1}$ respectively.

In a relation $F = a \sin(k_1x) + b \sin(k_2t)$,where $F$,$x$,and $t$ denote force,distance,and time respectively. The units of $k_1$ and $k_2$ are respectively:

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