In a rhombus ABCD,angle B = 80^{circ},then an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a rhombus $ABCD$,all sides are equal,so $AB = AD$. Since $AB = AD$,$	riangle ABD$ is an isosceles triangle. In a rhombus,adjacent angles are s

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(D) In a rhombus $ABCD$,all sides are equal,so $AB = AD$. Since $AB = AD$,$	riangle ABD$ is an isosceles triangle. In a rhombus,adjacent angles are supplementary,so $\angle A + \angle B = 180^{\circ}$. Given $\angle B = 80^{\circ}$,then $\angle A = 180^{\circ} - 80^{\circ} = 100^{\circ}$. In $	riangle ABD$,the sum of angles is $180^{\circ}$,so $\angle A + \angle ADB + \angle ABD = 180^{\circ}$. Since $AB = AD$,the base angles are equal: $\angle ADB = \angle ABD$. Therefore,$100^{\circ} + 2(\angle ADB) = 180^{\circ}$. $2(\angle ADB) = 80^{\circ}$. $\angle ADB = 40^{\circ}$.

In a rhombus $ABCD$,$\angle B = 80^{\circ}$,then $\angle ADB = \ldots$ (in $^{\circ}$)

Similar Questions

$A$ diagonal of a parallelogram bisects one of its angles. Show that it is a rhombus.

Which of the following is not true for a parallelogram?

Points $P$ and $Q$ have been taken on opposite sides $AB$ and $CD$ respectively of a parallelogram $ABCD$ such that $AP = CQ$ (see figure). Show that $AC$ and $PQ$ bisect each other.

Diagonals of a parallelogram $ABCD$ intersect at $O.$ If $\angle BOC = 90^{\circ}$ and $\angle BDC = 50^{\circ},$ then $\angle OAB$ is (in $^{\circ}$)

In rhombus $ABCD$,$\angle A = \angle B - 30^{\circ}$,then $\angle C = \ldots$ (in $^{\circ}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module