In a satellite,if the time of revolution is $T$,then the potential energy $(PE)$ is proportional to ..........

  • A
    $T^{1/3}$
  • B
    $T^3$
  • C
    $T^{-2/3}$
  • D
    $T^{-4/3}$

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Similar Questions

Choose the correct alternative:
$(a)$ If the zero of potential energy is at infinity,the total energy of an orbiting satellite is negative of its kinetic/potential energy.
$(b)$ The energy required to launch an orbiting satellite out of Earth's gravitational influence is more/less than the energy required to project a stationary object at the same height (as the satellite) out of Earth's influence.

In an orbit,if the time of revolution of a satellite is $T$,then the potential energy $(PE)$ is proportional to:

An artificial satellite moving in a circular orbit around the earth has a total (kinetic + potential) energy $E_0$. Its potential energy is

$A$ launching vehicle carrying an artificial satellite of mass $m$ is set for launch on the surface of the earth of mass $M$ and radius $R$. If the satellite is intended to move in a circular orbit of radius $7R$,the minimum energy required to be spent by the launching vehicle on the satellite is ($G$ is the gravitational constant).

The ratio of energy required to raise a satellite to a height $h$ above the earth's surface to that required to put it into the orbit at the same height is ($R=$ radius of earth).

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