In a series LCR resonance circuit,if we chang | vedclass

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(A) The resonance frequency of an $LCR$ circuit is given by $\omega_0 = 1 / \sqrt{LC}$. Since it depends only on $L$ and $C$,it remains constant when

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The bandwidth of the resonance circuit will increase.

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(A) The resonance frequency of an $LCR$ circuit is given by $\omega_0 = 1 / \sqrt{LC}$. Since it depends only on $L$ and $C$,it remains constant when resistance $R$ is changed.The bandwidth of an $LCR$ circuit is defined as $\Delta \omega = R / L$.Since the bandwidth $\Delta \omega$ is directly proportional to the resistance $R$ $(\Delta \omega \propto R)$,increasing the resistance $R$ will increase the bandwidth.The quality factor $Q$ is given by $Q = \omega_0 L / R = 1 / R \sqrt{L/C}$. Since $Q \propto 1/R$,increasing the resistance $R$ will decrease the quality factor.Therefore,the correct statement is that the bandwidth of the resonance circuit will increase.

In a series $LCR$ resonance circuit,if we change the resistance only,from a lower to higher value:

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