In a series $LCR$ circuit,the power dissipation occurs through

What will be the impedance of the circuit shown below in $\Omega$?

With an increase in the frequency of an $a.c.$ supply,the impedance of an $LCR$ series circuit:

In the circuit shown in the figure,if both the bulbs $B_1$ and $B_2$ are identical,then:

An $LCR$ series circuit with $R = 100\,\Omega$ is connected to a $200\,V, 50\,Hz$ $a.c.$ source. When only the capacitance is removed,the current lags the voltage by $60^o$. When only the inductance is removed,the current leads the voltage by $60^o$. The current in the circuit is.....$A$

In a series $LCR$ circuit, $R = 10 \ \Omega$ and the impedance $Z = 30 \ \Omega$. An $r.m.s.$ voltage of $210 \text{ V}$ is applied across the circuit. The true power consumed in the $AC$ circuit is: (in $\text{ W}$)