In a transistor amplifier,$\beta = 62$,$R_L = 5000\, \Omega$,and the internal resistance of the transistor is $R_i = 500\, \Omega$. The voltage amplification of the amplifier will be:

When $NPN$ transistor is used as an amplifier,

For a given transistor,if $\alpha = 0.95$,find the common emitter current gain $\beta$.

In a common base transistor circuit,the current gain is $0.98$. On changing emitter current by $5.00 \,mA$,the change in collector current is ......... $mA$.

An $n-p-n$ transistor is connected in common-emitter configuration as shown in the figure. If the collector current is $5 \text{ mA}$,$V_{BE} = 0.6 \text{ V}$,$V_{CE} = 3 \text{ V}$,and the common-emitter current amplification factor $\beta = 50$,then the values of $R_1$ and $R_2$ are respectively.

In an amplifier circuit,the value of the load resistance $R_L$ is $2 \text{ k}\Omega$. $A$ change of $10 \text{ }\mu\text{A}$ in the base current of the transistor results in a change of $1 \text{ mA}$ in the collector current. The change in the collector-emitter voltage $(V_{CE})$ is ....... $V$.