In a transistor amplifier,the base-emitter junction is forward-biased and the collector-emitter junction is reverse-biased. The current gain is defined as:
- A$\frac{\Delta I_{E}}{\Delta I_{B}}$
- B$\frac{\Delta I_{B}}{\Delta I_{E}}$
- C$\frac{\Delta I_{B}}{\Delta I_{C}}$
- D$\frac{\Delta I_{C}}{\Delta I_{B}}$
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$A$ transistor is connected in common emitter $(CE)$ configuration. The collector supply is $8\ V$ and the voltage drop across a resistor of $800\,\Omega$ in the collector circuit is $0.5\ V$. If the current gain factor $\alpha$ is $0.96$,find the base current in $\mu A$.
Difficult
View SolutionFor a transistor amplifier in a common-emitter configuration,given the load resistance $R_L = 1 \ k\Omega$,$h_{fe} = 50$,and $h_{oe} = 25 \ \mu A/V$,calculate the current gain $(A_i)$.
Medium
View SolutionIn the following common emitter circuit,$\beta=100$ and $V_{CE}=7 \text{ V}$. If $V_{BE}$ is negligible,then the base current is (in $\text{ mA}$)
Which one of the operations of $n-p-n$ transistor differs from that of $p-n-p$ transistor?
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DifficultMHT CET 2026
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