$A$ transistor is connected in common emitter $(CE)$ configuration. The collector supply is $8\ V$ and the voltage drop across a resistor of $800\,\Omega$ in the collector circuit is $0.5\ V$. If the current gain factor $\alpha$ is $0.96$,find the base current in $\mu A$.

The dc common emitter current gain of an $n-p-n$ transistor is $50$. The potential difference applied across the collector and emitter of a transistor used in $CE$ configuration is $V_{CE} = 2 \ V$. If the collector resistance $R_{C} = 4 \ k\Omega$,the base current $(I_{B})$ and the collector current $(I_{C})$ are:

For a transistor,$\beta = 100$. The value of $\alpha$ is

In the following common emitter configuration, an $NPN$ transistor with current gain $\beta = 100$ is used. The output voltage of the amplifier will be

In a silicon transistor,a change of $7.89 \, mA$ in the emitter current produces a change of $7.8 \, mA$ in the collector current. What change in the base current is necessary to produce an equivalent change in the collector current (in $mA$)?

The input voltage applied to a $CE$ amplifier is $v_i = 0.2 \sin(1000t) \text{ V}$. If the voltage gain of the amplifier is $10$,the equation for the output voltage is ....... $\text{V}$.