In a triangle $ABC$ with usual notations,if $\frac{\cos A}{a} = \frac{\cos B}{b} = \frac{\cos C}{c}$,then the triangle is equilateral. If the side length is $a = \sqrt{6}$,find the area of the triangle.

  • A
    $\frac{\sqrt{3}}{2}$ sq. units
  • B
    $\frac{3 \sqrt{3}}{2}$ sq. units
  • C
    $\frac{2}{\sqrt{3}}$ sq. units
  • D
    $\frac{5 \sqrt{3}}{2}$ sq. units

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