In a triangle ABC with usual notations,if b s | vedclass

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(B) Given the expression $b \sin C(b \cos C + c \cos B) = 42$. Using the projection rule,we know that $a = b \cos C + c \cos B$. Substituting this int

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$21 	ext{ sq.units}$

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(B) Given the expression $b \sin C(b \cos C + c \cos B) = 42$. Using the projection rule,we know that $a = b \cos C + c \cos B$. Substituting this into the expression,we get $b \sin C(a) = 42$. This simplifies to $ab \sin C = 42$. The area of a triangle $ABC$ is given by $\Delta = \frac{1}{2} ab \sin C$. Substituting the value $ab \sin C = 42$ into the area formula,we get $\Delta = \frac{1}{2} 	imes 42 = 21 	ext{ sq.units}$.

In a triangle $ABC$ with usual notations,if $b \sin C(b \cos C + c \cos B) = 42$,then the area of triangle $ABC$ is:

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