In a triangle $ABC$, $a=5$, $b=4$ and $\tan \frac{C}{2}=\sqrt{\frac{7}{9}}$, then its inradius $r=$

  • A
    $\frac{\sqrt{7}}{2}$
  • B
    $2 \sqrt{7}$
  • C
    $\frac{9}{\sqrt{7}}$
  • D
    $\frac{4}{\sqrt{7}}$

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