In a triangle $ABC$,$\angle B < \angle C$ and the values of $B$ and $C$ satisfy the equation $2 \tan x - k (1 + \tan^2 x) = 0$,where $0 < k < 1$. Then the measure of angle $A$ is:
- A$\pi / 3$
- B$2\pi / 3$
- C$\pi / 2$
- D$3\pi / 4$
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