In a Young's double slit experiment, the slit | vedclass

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(D) The distance of the $n^{th}$ bright fringe from the central fringe is given by $y_n = \frac{n \lambda D}{d}$.The distance between the $4^{th}$ bri

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(D) The distance of the $n^{th}$ bright fringe from the central fringe is given by $y_n = \frac{n \lambda D}{d}$.The distance between the $4^{th}$ bright fringe on both sides is $2 y_4 = 2 	imes \frac{4 \lambda D}{d} = \frac{8 \lambda D}{d}$.Given: $2 y_4 = 2.4 \, cm = 2.4 	imes 10^{-2} \, m$, $D = 1.5 \, m$, $d = 0.3 \, mm = 0.3 	imes 10^{-3} \, m$.Using $\lambda = \frac{c}{f}$, we have $\frac{8 	imes c 	imes D}{f 	imes d} = 2.4 	imes 10^{-2}$.Substituting the values: $\frac{8 	imes (3 	imes 10^8) 	imes 1.5}{f 	imes (0.3 	imes 10^{-3})} = 2.4 	imes 10^{-2}$.$\frac{36 	imes 10^8}{f 	imes 0.3 	imes 10^{-3}} = 2.4 	imes 10^{-2}$.$f = \frac{36 	imes 10^{11}}{0.3 	imes 2.4 	imes 10^{-2}} = \frac{36 	imes 10^{13}}{0.72} = 50 	imes 10^{13} = 5 	imes 10^{14} \, Hz$.

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