In an $A.C.$ circuit,$V$ and $I$ are given by:
$V = 100 \sin(100 t) \text{ V}$
$I = 100 \sin(100 t + \pi/3) \text{ mA}$
The power dissipated in the circuit is:

  • A
    $10^4 \text{ W}$
  • B
    $10 \text{ W}$
  • C
    $2.5 \text{ W}$
  • D
    $5 \text{ W}$

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