In an $AC$ circuit,$V$ and $I$ are given by $V = 150 \sin(150t) \, V$ and $I = 150 \sin(150t + \frac{\pi}{3}) \, A$. The power dissipated in the circuit is $W$.

  • A
    $5625$
  • B
    $2812.5$
  • C
    $11250$
  • D
    $0$

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