In an $L-C-R$ circuit,the capacitance is changed from $C$ to $4 C$. For the same resonant frequency,the inductance should be changed from $L$ to

$A$ $750\, Hz$,$20\, V$ (rms) source is connected to a resistance of $100\, \Omega$,an inductance of $0.1803\, H$,and a capacitance of $10\, \mu F$,all in series. The time in which the resistance (heat capacity $2\, J/^{\circ}C$) will get heated by $10^{\circ}C$ (assume no loss of heat to the surroundings) is close to $.....s$.

In an $R-L-C$ series circuit, the potential difference across each element is $20 \, V$. If the value of the resistance $R$ is doubled, what will be the potential difference across $R, L$, and $C$ respectively?

In an $LCR$ series circuit,if $R = X_L = 2X_C$,find the impedance and the phase difference between the current and the voltage.

What is the impedance of an $L-C-R$ series $AC$ circuit?

An $AC$ source is connected in the given series $LCR$ circuit. The $RMS$ potential difference across the capacitor of $20 \mu F$ is . . . . . . $V$.
$V = 50 \sqrt{2} \sin 100 t$ volt