In an $n-p-n$ transistor, $95 \%$ of emitted electrons reach the collector. If the base current is $2 \text{ mA}$, then the collector current is (in $\text{ mA}$)

  • A
    $19$
  • B
    $38$
  • C
    $9.5$
  • D
    $48$

Explore More

Similar Questions

For a transistor,the current ratio $\beta_{dc}$ is defined as the ratio of:

When a signal is applied to the input of a transistor,it is found that the output signal is phase-shifted by $180^{\circ}$. The transistor configuration is:

In an $n-p-n$ transistor,

An $npn$ transistor operates as a common emitter amplifier,with a power gain of $60\, dB$. The input circuit resistance is $100\,\Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ is:

$10^{10}$ electrons enter the emitter of a junction transistor in a time of $0.4 \mu s$. If $5 \%$ of the electrons are lost in the base, then the collector current is (in $\text{ mA}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo